Two cars simultaneously left Points A and B and headed towards each other, and met after 3 hours and 15 minutes. The distance between points A and B is 364 miles. What is the speeds of the cars, if one of the cars travels 12 mph faster than the other?

Answer:   50 mph, 62 mphStep-by-step explanation:Their total speed is found from ...   speed = distance/time   speed = (364 mi)/(3.25 h) = 112 mi/hIf s is the speed of the slower car, then ...   s + (s+12) = 112 . . . . . their total speed is 112 mph   2s = 100 . . . . . . . . . . simplify, subtract 12   s = 50 . . . . . . . the speed of the slower car   s+12 = 62 . . . . the speed of the faster car